Question

g(x)=square root of x-5 .. fins the domain and sketch the graph..

Answer 1

\[\sqrt{x-5}\] is the domain \[x>5\]

Answer 2

Well, you can't find a square root of a negative number, so the values that make the expression under the radical negative are not in the domain.

Answer 3

Actually, you want x>=5, because x can be 5. You can take the square root of 0.

Answer 4

i see..

Answer 5

how about sketching the graph???

Answer 6

Do you know about finding the inverse function?

Answer 7

cant remember :/

Answer 8

This is a very bad description, but basically you take a function and switch the x and y values to get its inverse.

Answer 9

is this a inverse function?

Answer 10

So, for example, if I had a function that had (4,5) as a pair, I'd switch it, and the corresponding coordinates for the inverse function would be (5,4).

Answer 11

ok ..

Answer 12

This function is the inverse of (x-5)^2 = y. Can you plot some points on that graph?

Answer 13

The little ^2 means "squared."

Answer 14

Actually, something is wrong with my explanation. So just plot some points on the graph of the original function and see what you get.

Answer 15

Doesn't it look a bit like a parabola? That's what I always think.

Answer 16

\[\sqrt{x-5}\] is same as \[\left( x-5 \right)^2\] ?????????????

Answer 17

No, it isn't. Sorry about that. Try plotting some points, like I suggested above.

Answer 18

well, this is what i got if x=6, y=1 ...

Answer 19

is it correct?

Answer 20

do you know how \(\large y=\sqrt{x} \) looks like?

Answer 21

no...