Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Which equation matches the graph shown? (will attach graph and answer choices in a sec!)

OpenStudy (anonymous):

GRAPH

OpenStudy (anonymous):

Answer choices A,B,C,D top to bottom

OpenStudy (anonymous):

roots

OpenStudy (anonymous):

then y-int

OpenStudy (anonymous):

i think B and D are out because that would mean the graph would be going upwards and the graph is going downwards... am i right??? the answer choices are between A and C??

OpenStudy (anonymous):

y int=2 roots= (-2,0) and (1,0) ??? idk is that right??

OpenStudy (anonymous):

yes thats true

OpenStudy (anonymous):

yes then use in root form

OpenStudy (anonymous):

nice elimenation teqnique

OpenStudy (anonymous):

so how do i solve?? whats the root form again?? ;O is it y=a(x-h)^2+k ???is that it?

OpenStudy (anonymous):

oh and thanks! :D

OpenStudy (anonymous):

\[y=a(x-x _{1})(x-x _{2})\]

OpenStudy (anonymous):

ohhh okay so what do i plug in again?

OpenStudy (anonymous):

i always forget this one :/

OpenStudy (anonymous):

first plug roots in (planting)

OpenStudy (anonymous):

okay which ones do i plug? can u pls show me?? I'm a bit confused :/

OpenStudy (anonymous):

both roots

OpenStudy (anonymous):

x intercepts

OpenStudy (anonymous):

i do them separately? like i do it twice? once for each root?

OpenStudy (anonymous):

no same time

OpenStudy (anonymous):

\[y=a(x+2)(x-1)\]

OpenStudy (anonymous):

did u just plug them in?

OpenStudy (anonymous):

and what do i do now then?

OpenStudy (anonymous):

plug y-int

OpenStudy (anonymous):

into the y value part?

OpenStudy (anonymous):

@Jonask what do i do now>????

OpenStudy (anonymous):

\[2=a(0-1)(0+2)\]

OpenStudy (anonymous):

so 2=a(-1)(2) 2=a(-2) -1=a ?? is that right?

OpenStudy (anonymous):

@jonask is that right?? if so, what do i do next??

OpenStudy (anonymous):

yes,you are done \[y=-1(x-1)(x+2)\]

OpenStudy (anonymous):

A

OpenStudy (anonymous):

awesome!! thank you soooo much!! :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!