A ball is thrown upward from the top of a building 160 ft high with an initial velocity of 48 ft/sec.
Find the maximum height the ball reaches. Position Formula is -16t^2+48T+160

Question

A ball is thrown upward from the top of a building 160 ft high with an initial velocity of 48 ft/sec.
Find the maximum height the ball reaches. Position Formula is -16t^2+48T+160

anonymous · Answer

s = -16t²+48t +160 
Vertex coordinate ( h, k)
h = ...?

anonymous · Answer

I'm confused on what you mean?

anonymous · Answer

Do you know what vertex is?

anonymous · Answer

Yeas, but s is the position function so it looks like this right?|dw:1350177313835:dw|

anonymous · Answer

Yes, vertex point in this case is maximum point!

anonymous · Answer

Do know how to find vertex coordinate?

anonymous · Answer

No, I guess not then, how should I go about doing that?

anonymous · Answer

h = -b/2a

anonymous · Answer

Thank you!