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Mathematics 19 Online
OpenStudy (anonymous):

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function. f(x) = -2x4 + 4x3 + 3x2 + 18

OpenStudy (anonymous):

please help!!

OpenStudy (anonymous):

i cant figure it out :(

OpenStudy (anonymous):

(the factors of 18)/(the factors of -2)

OpenStudy (anonymous):

2 .. 3 ..-2 ???

OpenStudy (anonymous):

wait.. nvm

OpenStudy (anonymous):

ie {+/- (1,2,3,6,9,18) } / { +/-(1,2)}

OpenStudy (anonymous):

hmmmm.. so would tht be the answer?

OpenStudy (anonymous):

all the numbers in that list..

OpenStudy (anonymous):

there all the answers?

OpenStudy (anonymous):

"...a list of all possible rational zeros of the function."

OpenStudy (anonymous):

so in the answer spot would i just put {+/- (1,2,3,6,9,18) } / { +/-(1,2)}

OpenStudy (anonymous):

probably the actual numbers themselves...

OpenStudy (anonymous):

ohhok thnkyou

OpenStudy (anonymous):

you sure you didn't leave a term out of that expression?

OpenStudy (anonymous):

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function. f(x) = -2x4 + 4x3 + 3x2 + 18 this is the question that is asked on my quiz ^^^?

OpenStudy (anonymous):

there's no term with 'x' ? you're sure??

OpenStudy (anonymous):

yeah im sure.. i copied that straight from the page

OpenStudy (anonymous):

so would those still be right? or no?

OpenStudy (anonymous):

i looked at tht nd im still comfused :(

OpenStudy (anonymous):

naw there's something off about your problem... it's either not* supposed to be using rational roots theorem or the equation isn't right.

OpenStudy (anonymous):

see thts wat i thought too could it be no zeros?

OpenStudy (anonymous):

it has real zeros, you just won't find them from rational roots theorem.

OpenStudy (anonymous):

hmm.. idk;/

OpenStudy (anonymous):

Okee... the constant term is 18 and the coefficient of the highest degree term is -2. Descartes said that if you take all the factors, positive and negative, of those two and make them into all the possible fractions (it's a lot of fractions in this case) one of them is probably a zero. If we call all the factors of the constant term "p" and all the factors of the -2 "q", then we make the fractions like p/q. Try it, it's fun. But it doesn't always work... I prefer graphing.

OpenStudy (anonymous):

so... +/- factors of 18: 1,2,3,6,9,18,-1,-2,-3,-6,-9,-18 and... factors of -2: 1,2,-1,-2 When you make the fractions, you'll get 48 fractions, but some of them will reduce to the same values.

OpenStudy (anonymous):

1/1, 2/1, 3/1, 6/1, 9/1, 18/1, -1/1, -2/1, -3/1, -6/1, -9/1, -18/1, 1/2, 2/2, 3/2...

OpenStudy (anonymous):

so those ^^^ would be the answer id put?

OpenStudy (anonymous):

to the question?

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