In the function y-1=(4x)^2+7 , what effect does the number 4 have on the graph, as compared to the graph of y=x^2 ? A. It stretches the graph vertically by a factor of 4. B. It shrinks the graph horizontally to 1/4 the original width. C. It shrinks the graph vertically to 1/4 the original height. D. It stretches the graph horizontally by a factor of 4. ***Idk what this one means :/ please explain :) thanks! :D
are you sure it's not y-1=4(x)^2+7 or y-1=4x^2+7
here ill draw it out :)
|dw:1350189437304:dw|
hmm interesting
yeah idk what it means :/
do u understand it? :D
i think it's A, but that would mean it would have to be either y-1=4(x)^2+7 or y-1=4x^2+7 the coefficient for the x^2 term dictates how you stretch/compress the parent function
is there a difference when u change it like that??
but the way you drew it, it's way off (you would square 4 to get 16, but that's not an answer choice)
yes there is
here is exactly how it looks :)
idk if that helps? haha
wait but didn't u say earlier the k part is the up/down?? and k=8 in this equation right?? so would it still be stretching vertically ??? is the effect of the 4 a VERTICAL stretch?
no, that's shifting vertically
4 is part of the vertical stretch, but it's really 4^2 = 16
wait i'm confused.. so how do i find the answer to this??
there has to be a typo
my guess is that they meant to say y-1=4x^2+7
here is something i found :) idk if that helps tho cuz i think u know this already haha
i do and those aren't used in this particular case
okay haha is it this that is used?
oh, ok, i see what they're using
x^2 becomes (4x)^2 so they replaced 'x' with '4x'
so yeah? the thingy i just posted is what we are using?
agreed?
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