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Mathematics 21 Online
OpenStudy (anonymous):

Which of the following equations will produce the graph shown below? (will attach graph and answer choices in a sec!)

OpenStudy (anonymous):

GRAPH

OpenStudy (anonymous):

answer choices A,B,C,D from top to bottom

jimthompson5910 (jim_thompson5910):

what is the vertex of that given graph?

OpenStudy (anonymous):

(-2,-2) ???

jimthompson5910 (jim_thompson5910):

so you had to do what to the vertex to get it there?

jimthompson5910 (jim_thompson5910):

the vertex of y = x^2

OpenStudy (anonymous):

idk

jimthompson5910 (jim_thompson5910):

the vertex of y = x^2 is what?

OpenStudy (anonymous):

(-2,-2) ?

jimthompson5910 (jim_thompson5910):

no, that's the vertex of this unknown graph

jimthompson5910 (jim_thompson5910):

not y = x^2

OpenStudy (anonymous):

oh then idk haha :/

jimthompson5910 (jim_thompson5910):

the vertex of y = x^2 is (0,0) sound familiar?

OpenStudy (anonymous):

ohhh okay haha i see :) so what do i do next?

jimthompson5910 (jim_thompson5910):

so how do we go from (0,0) to (-2,-2)?

OpenStudy (anonymous):

subtract 2 i mean

jimthompson5910 (jim_thompson5910):

left or right?

OpenStudy (anonymous):

left

OpenStudy (anonymous):

i think...

jimthompson5910 (jim_thompson5910):

how many units to the left?

OpenStudy (anonymous):

2 units to the left

jimthompson5910 (jim_thompson5910):

and how many units down?

OpenStudy (anonymous):

2 units down right?

jimthompson5910 (jim_thompson5910):

so h = -2 and k = -2 the only thing left to do is find the value of 'a'

OpenStudy (anonymous):

howdo i do that?

jimthompson5910 (jim_thompson5910):

what's another point that's on the graph (other than the vertex)?

OpenStudy (anonymous):

(-1,1) and there is also (-3,1)

OpenStudy (anonymous):

what do i do now? :D

jimthompson5910 (jim_thompson5910):

so plug that into y = a(x-h)^2 + k along with h = -2 and k = -2 to get y = a(x-h)^2 + k y = a(x-(-2))^2 + (-2) ... Plug in h = -2 and k = -2 y = a(x+2)^2 - 2 1 = a(-1+2)^2 - 2 ... Then plug in x = -1 and y = 1 1 = a(1)^2 - 2 1 = a - 2 Keep going to solve for 'a'

OpenStudy (anonymous):

a=3 ?

jimthompson5910 (jim_thompson5910):

good

OpenStudy (anonymous):

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