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Mathematics 18 Online
OpenStudy (anonymous):

Isn't the net external force of an object always 0?

OpenStudy (anonymous):

only if it's not accelerating

OpenStudy (anonymous):

well a net external force on the car is the same as the Sum of the forces on the car which should always equal zero.. here's my question because when i read net external forces i read the sum of all the forces

OpenStudy (anonymous):

not accounting their signs

OpenStudy (anonymous):

The sum of forces equals zero only in equilibrium.

OpenStudy (anonymous):

say in calculus when you had a curve that went below the line , the net area would be the (positive area)+(negative area)

OpenStudy (anonymous):

|dw:1350452696014:dw|

OpenStudy (anonymous):

so now accounting newtons law, for every force there is an oppositve equal force

OpenStudy (anonymous):

wouldn't the net external force on this object be \[F_o-f_s-T=0\]

OpenStudy (anonymous):

Only if it is not moving.

OpenStudy (anonymous):

since external forces would be(static friction, tension, and the object

OpenStudy (anonymous):

what if it's moving

OpenStudy (anonymous):

Friction becomes kinetic and motion will depend on which force is greatest.

OpenStudy (anonymous):

ah you're asking about action-reaction pairs?

OpenStudy (anonymous):

|dw:1350453177211:dw|

OpenStudy (anonymous):

this is what i'm asking about. when i hear net external force i think of the sum of the forces acting upon object 1|dw:1350453314890:dw|

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