Ask
your own question, for FREE!
Mathematics
21 Online
OpenStudy (lgbasallote):
math question inside
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
What is the truth value of the quantification \(\forall x(x^2 \ge x)\), where the domain consists of all real numbers
OpenStudy (vishweshshrimali5):
If x < 1 and x>0 then it is not true
OpenStudy (lgbasallote):
why so?
OpenStudy (vishweshshrimali5):
or i should say
it is not satisfied for
-1<x<1
OpenStudy (vishweshshrimali5):
Because in all that region we have proper fractions
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
oh. the fractions
OpenStudy (lgbasallote):
didn't think of that
OpenStudy (vishweshshrimali5):
Yep
OpenStudy (lgbasallote):
the fraction's arent just -1 < x < 1 by the way...
OpenStudy (vishweshshrimali5):
That is why I said proper fractions
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (vishweshshrimali5):
Or I should say
0<|x|<1
OpenStudy (vishweshshrimali5):
This is the set of the value of real numbers for which it is not satisfied
OpenStudy (lgbasallote):
2 1/2 doesn't satisfy it either...
OpenStudy (cruffo):
if x = -1/2 then x^2 = +1/4 so no worries about the negatives
OpenStudy (vishweshshrimali5):
let me see
5/2 = 2.5
sqauring
6.25 > 2.5
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (vishweshshrimali5):
Wrong calculation lgba
OpenStudy (vishweshshrimali5):
correct @cruffo
OpenStudy (cruffo):
the only time the graph of x^2 is below x is on the interval (0,1) not including the endpoints.
OpenStudy (vishweshshrimali5):
absolutely ....... correct
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!