The average value of a certain type of automobile was $13,140 in 1992 and depreciated to $9420 in 1997. Let y be the average value of the automobile in the year x, where x = 0 represents 1992. Write a linear equation that models the value of the automobile in terms of the year x.
A) y = -744x + 9420
B) y = - 1/744x - 9420
C) y = -744x + 13,140
D) y = -744x + 5700
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OpenStudy (anonymous):
anything?
OpenStudy (darkprince14):
try to test each given equation with x =5...it's kinda the last resort coz i forgot how to solve problems like this..sorry..
OpenStudy (anonymous):
@jim_thompson5910 can you help?
OpenStudy (anonymous):
do you know how to find the slope of a line if I give you two points?
OpenStudy (anonymous):
yes
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jimthompson5910 (jim_thompson5910):
when x = 0, y = 13140
jimthompson5910 (jim_thompson5910):
so plugging in x = 0 into choice A for example gives us
y = -744x + 9420
y = -744(0) + 9420
y = 0 + 9420
y = 9420
which is NOT the answer (we want y = 13140)
jimthompson5910 (jim_thompson5910):
so choice A is out
OpenStudy (anonymous):
oh
OpenStudy (darkprince14):
that's what they call trial and error XD..
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OpenStudy (anonymous):
so is it c.
OpenStudy (darkprince14):
try the given equation on letter be and see if it works... do the same for c and d...
jimthompson5910 (jim_thompson5910):
it is C
OpenStudy (anonymous):
yay! thank you guys!
hero (hero):
Hottmess!, you need to go back to that question you think you finished, but didn't.