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OpenStudy (anonymous):
\[f(x)=\sqrt[3]{x+8}\]
OpenStudy (anonymous):
a. f-1(x) = x - 8
b. 1/x^3-8
C) f-1(x) = x^3 + 64
D) f-1(x) = x^3 - 8
OpenStudy (anonymous):
to find the inverse of a function what you do is switch x and f(x) and solve for f(x)
OpenStudy (anonymous):
so \[x = \sqrt[3]{f(x) + 8}\]
OpenStudy (anonymous):
can you solve for f(x)?
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OpenStudy (anonymous):
no im sorry i dont understand.
OpenStudy (anonymous):
No, you replace the values of X with Y. Then solve for Y.
OpenStudy (anonymous):
f(x) is the same as y just written differently
OpenStudy (anonymous):
So it would then look like: \[\sqrt[3]{y+8} = x\]
now solve for Y
OpenStudy (anonymous):
how do i solve for y. is 8^3
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OpenStudy (anonymous):
So cube both sides and subtract eight from both sides. You should then have y = x^3 - 8
OpenStudy (anonymous):
If you are finding a number multiplied three times to get (y+8) raising its power to three would be the opposite action. That's why it cancels the radical sign.
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
so is that it or more?
OpenStudy (anonymous):
That's it! Unless you have any questions or misunderstandings I can tro to help you.
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