Find the inverse of the one-to-one function.
\[f(x)=\sqrt[3]{x+8}\]
a. f-1(x) = x - 8 b. 1/x^3-8 C) f-1(x) = x^3 + 64 D) f-1(x) = x^3 - 8
to find the inverse of a function what you do is switch x and f(x) and solve for f(x)
so \[x = \sqrt[3]{f(x) + 8}\]
can you solve for f(x)?
no im sorry i dont understand.
No, you replace the values of X with Y. Then solve for Y.
f(x) is the same as y just written differently
So it would then look like: \[\sqrt[3]{y+8} = x\] now solve for Y
how do i solve for y. is 8^3
So cube both sides and subtract eight from both sides. You should then have y = x^3 - 8
If you are finding a number multiplied three times to get (y+8) raising its power to three would be the opposite action. That's why it cancels the radical sign.
oh
so is that it or more?
That's it! Unless you have any questions or misunderstandings I can tro to help you.
No i got it now thank you for your help!
You're welcome! :)
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