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Mathematics 18 Online
OpenStudy (anonymous):

Find the inverse of the one-to-one function.

OpenStudy (anonymous):

\[f(x)=\sqrt[3]{x+8}\]

OpenStudy (anonymous):

a. f-1(x) = x - 8 b. 1/x^3-8 C) f-1(x) = x^3 + 64 D) f-1(x) = x^3 - 8

OpenStudy (anonymous):

to find the inverse of a function what you do is switch x and f(x) and solve for f(x)

OpenStudy (anonymous):

so \[x = \sqrt[3]{f(x) + 8}\]

OpenStudy (anonymous):

can you solve for f(x)?

OpenStudy (anonymous):

no im sorry i dont understand.

OpenStudy (anonymous):

No, you replace the values of X with Y. Then solve for Y.

OpenStudy (anonymous):

f(x) is the same as y just written differently

OpenStudy (anonymous):

So it would then look like: \[\sqrt[3]{y+8} = x\] now solve for Y

OpenStudy (anonymous):

how do i solve for y. is 8^3

OpenStudy (anonymous):

So cube both sides and subtract eight from both sides. You should then have y = x^3 - 8

OpenStudy (anonymous):

If you are finding a number multiplied three times to get (y+8) raising its power to three would be the opposite action. That's why it cancels the radical sign.

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

so is that it or more?

OpenStudy (anonymous):

That's it! Unless you have any questions or misunderstandings I can tro to help you.

OpenStudy (anonymous):

No i got it now thank you for your help!

OpenStudy (anonymous):

You're welcome! :)

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