Question

Find the distance between the pair of points.

Answer 1

\[(3\sqrt{7},2) and (6\sqrt{7},1)\]

Answer 2

A) 8
B) 64
C) 32
D) 7

Answer 3

distance = \[\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\]

Answer 4

The distance formula above comes from the Pythagorean Theorem. You can read up on it online if you're curious.

Recall like terms. because \[3\sqrt{7} \] and \[6\sqrt{7} \]share the same number in the radical sign, they can be subtracted. So subtract, square, and add.

Answer 5

so
\[3\sqrt{7}-6\sqrt{7}=-3\sqrt{7}\]
square it and you get
\[9\times7\]
notice the radical sign disappeared.
now solve for the Y components.

Answer 6

\[\sqrt{(9\times7)+(2-1)^{2}}\]

Answer 7

i dont know i keep coming up with wrong numbers

Answer 8

\[\sqrt{63+1}\]
so the square root of 64 (two numbers multipled to get 64) would be 8.

Show me what you got? I'll write the full problem for you.

Answer 9

for the second one -1+4=3

Answer 10

for (2-1)^2 i got 3

Answer 11

\[\sqrt{(3\sqrt{7}-6\sqrt{7})^{2}+(2-1)^{2}}\]

Answer 12

Oh, you made a mistake. You should subtract one from two. so just simply 2-1.

Answer 13

Maybe you over thought it :)

Answer 14

i think i wrote the problem wrong.

Answer 15

Subtract inside the parenthesis first. People often forget and add. It's a common mistake.

Answer 16

i did x^2-x^1-y^2-y^1

Answer 17

Oh, the formula the person above provided is using "subscripts" these aren't exponents.

Answer 18

There are two X values and two Y values in this problem. The 1 and 2 show this distinction

Answer 19

ugh i didnt mean to put exponets

Answer 20

can you help me with two more problems ?

Answer 21

sure, i'll do what I can. Go ahead and post them.

Answer 22

thank you

Answer 23

Of course ! :)