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Can someone show me way \[\sqrt{(1-6i)^{2}+4(7+9i)} = 3+4i\]
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why*
you could maybe square both sides? does it work?
Well, I don't have the answer 3+4i from the beginning so that wouldn't work
@mukushla could you please check this out?
simplify under radical first
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\[\sqrt{(-35-12i)+(28+36i)}\]
?
yes right and..simplify further
\[\sqrt{-7+24i}\]
now see this ... very complete article about taking square root of a complex number
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Ok, thanks :)
no problem
That pdf was really great, can't thank you enough! :D
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