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OpenStudy (anonymous):
How do I solve this equation??
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OpenStudy (anonymous):
(3^x)(4^(2x+1)) = 6^(x+2)
OpenStudy (anonymous):
break 6 and 4 into smallest primes n then simplify...i mean group similar terms
OpenStudy (nubeer):
have u studied log? u hVE TOO APPLY LOG ON BOTH SIDES.
OpenStudy (anonymous):
yeahh, i've done log and ln and all.
OpenStudy (asnaseer):
You do not need logs here. Follow the advice given by @akash123
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OpenStudy (nubeer):
Ok but i think akash method would be easier then log.
OpenStudy (anonymous):
but there's a multiplication of 2 numbers with different bases?? what do I do to fix that??
OpenStudy (anonymous):
sorry, i'm not understanding what I have to do here :P
OpenStudy (anonymous):
1st break 6 and 4 into smallest primes
4=2*2
6=3*2
OpenStudy (anonymous):
use (a*b)^n = a^n * b^n
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OpenStudy (anonymous):
ohhh, ok. now lemme solve till there, and see what i get.. thank youu :)
OpenStudy (anonymous):
ok..:)
OpenStudy (anonymous):
so i have (3^x)(2^4x) = 9(3^x)(2^x) ??
OpenStudy (anonymous):
group similar terms
OpenStudy (anonymous):
it shud have like this 3^(...) = 2^(...)
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OpenStudy (anonymous):
so then i get \[9 = 8^x\] and then i log it and whatever :P
OpenStudy (anonymous):
yes...:)
OpenStudy (anonymous):
AHA. i feel so smart :D
OpenStudy (anonymous):
good...:)...keep it up.
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