How do I solve this equation??
(3^x)(4^(2x+1)) = 6^(x+2)
break 6 and 4 into smallest primes n then simplify...i mean group similar terms
have u studied log? u hVE TOO APPLY LOG ON BOTH SIDES.
yeahh, i've done log and ln and all.
You do not need logs here. Follow the advice given by @akash123
Ok but i think akash method would be easier then log.
but there's a multiplication of 2 numbers with different bases?? what do I do to fix that??
sorry, i'm not understanding what I have to do here :P
1st break 6 and 4 into smallest primes 4=2*2 6=3*2
use (a*b)^n = a^n * b^n
ohhh, ok. now lemme solve till there, and see what i get.. thank youu :)
ok..:)
so i have (3^x)(2^4x) = 9(3^x)(2^x) ??
group similar terms
it shud have like this 3^(...) = 2^(...)
so then i get \[9 = 8^x\] and then i log it and whatever :P
yes...:)
AHA. i feel so smart :D
good...:)...keep it up.
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