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Mathematics 21 Online
OpenStudy (anonymous):

How do I solve this equation??

OpenStudy (anonymous):

(3^x)(4^(2x+1)) = 6^(x+2)

OpenStudy (anonymous):

break 6 and 4 into smallest primes n then simplify...i mean group similar terms

OpenStudy (nubeer):

have u studied log? u hVE TOO APPLY LOG ON BOTH SIDES.

OpenStudy (anonymous):

yeahh, i've done log and ln and all.

OpenStudy (asnaseer):

You do not need logs here. Follow the advice given by @akash123

OpenStudy (nubeer):

Ok but i think akash method would be easier then log.

OpenStudy (anonymous):

but there's a multiplication of 2 numbers with different bases?? what do I do to fix that??

OpenStudy (anonymous):

sorry, i'm not understanding what I have to do here :P

OpenStudy (anonymous):

1st break 6 and 4 into smallest primes 4=2*2 6=3*2

OpenStudy (anonymous):

use (a*b)^n = a^n * b^n

OpenStudy (anonymous):

ohhh, ok. now lemme solve till there, and see what i get.. thank youu :)

OpenStudy (anonymous):

ok..:)

OpenStudy (anonymous):

so i have (3^x)(2^4x) = 9(3^x)(2^x) ??

OpenStudy (anonymous):

group similar terms

OpenStudy (anonymous):

it shud have like this 3^(...) = 2^(...)

OpenStudy (anonymous):

so then i get \[9 = 8^x\] and then i log it and whatever :P

OpenStudy (anonymous):

yes...:)

OpenStudy (anonymous):

AHA. i feel so smart :D

OpenStudy (anonymous):

good...:)...keep it up.

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