Question

Let the function h be defined by h(x)=14+9m, x sq./4. If h(2m)=9m, what is one possible value
of m?

If h(2m)=

Answer 1

what do you mean by x sq./4 ?

Answer 2

x to the power of 2 divided by 4

Answer 3

hhmm..., it's confusing... :D
so, define a function h with
\[h(x) = 14 + 9m\]

if \[h(2m) = 9m\]
what is m?
right?
so what is \[\frac{ x ^{2} }{ 4 } ?\]

Answer 4

wouldn't you just plug in 2 from 2m?

Answer 5

are you sure that you don't mistype the question?

Answer 6

Let the function h be defined by h(x)=14+x to the power of 2 divided

by 4. If h(2m)=9m, what is one possible value of m?

Answer 7

the equation is 14+ 2m squared/4

Answer 8

ahh...,

so, \[h(x) = 14 + \frac{ x ^{2} }{ 4 }\]

if \[h(2m) = 9m\]

plug in x = 2m into the definition of the function

Answer 9

7 +m squared=h(x)

Answer 10

be careful, it's x = 2m, so it's (2m)^2

Answer 11

14+2m squared divided by 4

Answer 12

IF I cross cancel, I get 7+2m squared divided by 2

Answer 13

that gives me 7+ m squared=h(x)

Answer 14

how do you get 7 + 2m squared ?

Answer 15

14+2x squared divided b6 4

Answer 16

I cross cancel with 14 and 4, which gives me 7 and 2

Answer 17

it's plus, not multiply, right?
you cannot use 'cross cancel'

Answer 18

*addition I mean

Answer 19

ahh

Answer 20

then 14+ m squared/2

Answer 21

=h(x)

Answer 22

be careful, it's (2m)^2 = 2^2 x m^2 = 4m^2

Answer 23

really?

Answer 24

14+ m sq.=h(x)?

Answer 25

yes, it uses the properties of exponent (ab)^m = a^m x b^m
14 + m^2 = h(2m) = 9m
m^2 - 9m + 14 = 0

can you solve this quadratic equation?

Answer 26

wow

Answer 27

m=2 or 7

Answer 28

yup :)

Answer 29

next problem?