Question

tan x + cot x = 2

then find sin x .

Answer 1

\[\cfrac {1}{cot x} + cot x = 2\]
\[cot^2 x - 2cot x + 1 = 0\]
\[cot x = 1\]
\[cosec^2 x = 1+ cot^2 x = 2\]
\[cosec x = \pm \sqrt{2}\]
but answer given is sin x = \(\cfrac{1}{\sqrt{2}}\)
should not it be
sin x = \(\cfrac{1}{\pm\sqrt{2}}\)

Answer 2

@estudier
@experimentX

Answer 3

@goformit100