Question

Determine the input that yields the minimum value for the function f(x)=square root of (x^2-8x+41)
I just don't know how to find the input when it is the square root of

Answer 1

y = sqrt(x^2-8x+41) = sqrt((x-4)^2 + 25)
to get the minimum value, it should when x=4

Answer 2

so, just put x=4 to that function
what is the value of y will u get ?

Answer 3

y=f(x)

Answer 4

any way u can use derivative to get it, but i think thought one like on

Answer 5

Do you know calculus?