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Mathematics 19 Online
OpenStudy (anonymous):

Simplify the expression.

OpenStudy (anonymous):

\[\frac{ -20x-12 }{ -12 }\]

OpenStudy (anonymous):

is it -20x? :P

OpenStudy (anonymous):

No, but you can first cancel out the negatives. thus. \[\frac{ 20x -12 }{ 12 }\] then we can remove a commonality of two the c. \[\frac {20} {12}x - 12\] and we can then solve further.

OpenStudy (anonymous):

Okay.

OpenStudy (anonymous):

After that you can move 12 by adding it to both sides resulting \[\frac {20}{12}x = 12\] and It should be simple enough from there :)

OpenStudy (anonymous):

Okay! Thank you :)

OpenStudy (anonymous):

36/5?

OpenStudy (anonymous):

Hmm actually let me check that.something wasn't right there.

OpenStudy (anonymous):

Oops sorry, being too sleepy. I meant \[\frac{12x}{20} −1\] not 12. since it was supposed to be divided by 12

OpenStudy (anonymous):

I just multiplied by its reciprocal...

OpenStudy (anonymous):

aha, x3. I was wondering why it was -12. But thanks! For clearing that up.

OpenStudy (anonymous):

And Im making more stupid mistakes, I apologize. One trick to spot such mistakes it to Make sure to test results with the equation and make sure it = 0. Thus. here it is fully \[\frac{(-20x-12 )}{-12} = \frac{-20}{-12}x +1 = \frac{20}{12}x +1\]\[\frac{20}{12}x = -1\]\[20x = -12\]\[x=-\frac{12}{20}\] Thus \[\frac{(-20x-12 )}{-12} = 0 \] will true

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