Question

I need help with the Sign Chart of the Polynomial Equality.

2x^2-3x-5>0

Answer 1

\[2x ^{2}-3x-5>0 \]
\[2x ^{2}-3x-5=0\]
(2x-5)(x+1)=0

2x-5= 0.........x=5/2

x+1=0...........x=-1

my problem is how you put this in the sign graph?

Answer 2

you see what im saying?

Answer 3

you are looking for
(2x-5)(x+1) >0
this happens when the stuff on the left side is positive
that means if both (2x-5) and (x+1) are positive or
both (2x-5) and (x+1) are negative (two negatives give a positive)

Answer 4

that doesn't explain how i get the positive in the left, the negative in the middle, and the postive on the right...

Answer 5

First step is solve for
2x-5>0 and x+1>0
x > 5/2 and x>-1
both have to be true so x> 5/2

2nd step is solve for
2x-5<0 and x+1<0
x<5/2 and x<-1
both have to be true, so x<-1

those are the two conditions that solve your problem

Answer 6

jesus this is confusing lool... can you somehow elaborate on what i do after those steps?

Answer 7

because i already got em

Answer 8

or is this the answer on how to properly place the signs on the chart