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Mathematics 19 Online
OpenStudy (anonymous):

find the derivative of the function y = x^2csc5x

OpenStudy (anonymous):

product and chain rules. product rule is f(x)*g'(x) + f'(x)*g(x) Here are a few hints: derivative of x^2 = 2x use chain rule csc(5x) = -cot(u)csc(u) where u = 5x 2x*csc5x + x^2*(5csc5x*-csc5xcot5x) simplify your answer if you need to. The final answer should look like this x (2-5 x cot(5 x)) csc(5 x) Dont forget to click on the best response button :)

OpenStudy (anonymous):

thanks!

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