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solve what?
\[\frac{ [2(-1+h)^2 +4(-1+h)]+2 }{ h }\]
goodness. Give a minute...
Expand the square out, then factorize h out, then simplify!
would the square be factored out to (-1+2h+h^2) ?
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NO, h² - 2h + 1
oh you start with the variables the the digits ?
oh alright
( h -1)² = h² - 2h + 1
then i get this and it looks wrong o.O \[-2-4h+2h^2-4+4h-2\]
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= 2 (h² - 2h + 1) = 2h² - 4h + 2
but arent all the values that dont contain h cancel out at this point ?
( 2h² - 4h + 2) + ( 4h -4 ) + 2 = ...
2h^2-8
= 2h² / h = 2h
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i get -8 too though ? :S
i have -2-4-2 :S
( 2h² - 4h + 2) + ( 4h -4 ) + 2 = ..
( a - b)² = a² - 2ab + b² ( h -1)² = h² - 2h + 1
|dw:1350358557500:dw|
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