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how do i find the derivative of an exponential function?
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\[\frac{d}{dx}[e^x]=e^x\] \[\frac{d}{dx}b^x=b^x\ln(b)\]
im confused because my original function is 70e^.1673, i dont know how to get the derivative
The derivative of e to the x is e to the x, so, if \[f(x)=e^x\] then\[f'(x)=e^x\]
thanks
There's a great video on the proof here: http://www.khanacademy.org/math/calculus/differential-calculus/v/proof--d-dx-e-x----e-x?exid=special_derivatives (and a lot of great practice exercises, too).
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70e^.1673 is just a number. the derivative of a constant is zero
Ah gah, sorry, yes. My mind put an x in there. Not sure why. What I said is technically correct, just not the right answer to the question. :)
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