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Mathematics 20 Online
OpenStudy (anonymous):

What is 1/1/x?

OpenStudy (anonymous):

x

OpenStudy (anonymous):

1-over-anything is the reciprocal of that 'anything.'

OpenStudy (zarkon):

depends if you have \[\frac{1}{1/x}\] or \[\frac{1/1}{x}\]

OpenStudy (zarkon):

I assume it is the first not the second

OpenStudy (anonymous):

Explanation... please recall that we define exponent rules so they have the following properties: \[ (x^a)^b=x^{ab} \]Thus: \[ \frac{1}{x}=x^{-1}\implies\frac{1}{\frac{1}{x}}=\frac{1}{x^{-1}}=(x^{-1})^{-1}=x^{(-1)(-1)}=x^1=x \]

OpenStudy (zarkon):

if you don't specify then for 1/1/x the division is done from left to right 1/1 first..then divide by x

OpenStudy (anonymous):

Yes, but, the one stated is a trivial question in comparison to the other, so I'd imagine it'd be otherwise.

OpenStudy (zarkon):

then the OP should have typed 1/(1/x) ;)

OpenStudy (anonymous):

Ah, semantics, semantics. But, true enough.

OpenStudy (anonymous):

Parentheses, parentheses, my kingdom for more parentheses!

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