Question

Find the sum of the x- and y-intercepts of any tangent line to the curve √x+√y=√7.

Answer 1

i used implicit differentiation to get dy/dx= -√y/√x

Answer 2

yep,,now let x1,y1 be the point on the curve,
eqn of tangent at that point is then


y-y1 = -sqrt(y1/x1) (x-x1)


convert it into the form of y/a + x/b =1

a and b are y and x intercepts respectively..

just substitute in a+b

Answer 3

ahhh so the answer is 7! thanks got it

Answer 4

7 ?

Answer 5

ohh..maybe,,alright..

you'll also have to use the fact sqrt(x1) + sqrt(y1) = sqrt(7)

7 might be the ans ,,i dont know..

Answer 6

ya it is thanks