Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

Find the linear approximation of the function f(x) = 1 − x at a = 0. a) L(x)-? b) Use L(x) to approximate square root of 0.9 (Round your answers to four decimal places.)

OpenStudy (anonymous):

OpenStudy (anonymous):

Racist user alert.

OpenStudy (lgbasallote):

^?

OpenStudy (anonymous):

you've missed out on the last few posts..

OpenStudy (lgbasallote):

will look into it

OpenStudy (anonymous):

he posts under nazyma though..

OpenStudy (calculusfunctions):

@Nazym do you want to learn how to do linear approximations?

OpenStudy (anonymous):

Omg what did I do to you? Where am I being racist???

OpenStudy (anonymous):

Oh sorry, it's actually square root of 1 − x at a = 0.

OpenStudy (lgbasallote):

interesting.....he gets blackballed and decided to create a new account....

OpenStudy (calculusfunctions):

The linear approximation of a function f(x) at x = a is\[L(x)=f(a)+f \prime(a)(x -a)\]where L(x) is the linearization of f at a. Example: Find the linear approximation of\[f(x)=\sqrt{x -2}\]at a = 6 Solution:\[f \prime(x)=\frac{ 1 }{ 2\sqrt{x -2} }\] \[f \prime(6)=\frac{ 1 }{ 4 }\]and\[f(6)=4\] Now\[L(x) =f(6)+f \prime(6)(x -6)\] \[L(6)=4+\frac{ 1 }{ 4 }(x -6)\] \[L(6)=4+\frac{ 1 }{ 4 }x -\frac{ 3 }{ 2 }\] \[L(6)=\frac{ 1 }{ 4 }x+\frac{ 5 }{ 2 }\]Therefore the corresponding linear approximation is\[\sqrt{x -2}\approx \frac{ 1 }{ 4 }x +\frac{ 5 }{ 2 }\] Let me know if this helps!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!