Question

If ABCDE is a regular pentagon and diagonals EB and AC intersect at O, then what is the degree measure of angleEOC?

Answer 1

using the property that diagonals of regular pentagon trisect all the interior angles, we get
angle OAB = OBC = 36 degrees (108/3, angle A=angle B =108 degrees)
now can u find EOC ?

Answer 2

by first finding AOB

Answer 3

Can you explain further? Sorry I can't understand :3

Answer 4

diagonals of regular pentagon trisect all the interior angles
so,
angle ABO will be 1/3 times interior angle ABC
so, angle ABO = 36
similarly angle BAO = 36

so angle AOB will be 180 -36-36
(because angle in a triangle sum upto 180)

and since EOC is vertical to AOB
EOC = AOB

Answer 5

how do you know that the interior angle of ABC is 108?

Answer 6

how do you find the angle A is 108 as well as the angle B?
sorry I'm confused

Answer 7

So EOC is 108?

Answer 8

yes