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lim x goes to 1 [(1+3x)/1+4x^2+3x^4]^3
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give me the answers with the steps.. thanks
u can directly put x=1, in that function as it does not lead to any indeterminate form
Follows from continuity...
And the fact that the denominator is not 0 at x = 1
is 64/216 the answer ?
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Could you show how you got that?
[1+3(1)]^3 = 64
mhmm... and the denominator?
512 (1+4+3)^3
That's right.... so 64/512... this is....?
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1/8 .. is that the answer ???
You got it :)
thanks
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