Question

(w-4)^2=2w^2-7w-4

Answer 1

w as in complex a+bi

Answer 2

?

Answer 3

It just says solve for w. Is that what you mean?

Answer 4

okey then I guess it's not complex

Answer 5

Well then you start by distrubuting the left term, do you know how to do that?

Answer 6

yes? w^2-4^2?

Answer 7

Not exactly don't forget that:\[(a+b)^{2}=a^{2}+2ab+b ^{2}\]

Answer 8

\[w ^{2}-8w+16 =2w ^{2}-7w-4\]

Answer 9

\[-w ^{2}-w+20=0\]

Answer 10

\[w ^{2}+w-20=0\]

Answer 11

\[w= \frac{ 1 }{ 2 } \pm \sqrt{\frac{ 1^{2} }{ 2^{2}}+20}\]

Answer 12

\[w= \frac{ 1 }{ 2 } \pm \sqrt{\frac{ 81 }{4 }} = \frac{ 1 }{ 2 } \pm \frac{ 9 }{ 2 }\]

Answer 13

The two solutions which satisfies the equation are
\[w _{1}=5; w _{2}=-4\]