Question

if alpha beta and gamma are roots of the equation(x-2)(x^2+6x-11)=0
find (alpha+beta+gamma)

Answer 1

answer plz

Answer 2

\[\alpha=2\]
\[\beta=\frac{ -6+\sqrt{6^2-4(1)(-11)} }{ 2 }\]
\[\Gamma =\frac{ -6-\sqrt{6^2-4(1)(-11)} }{ 2 }\]
\[\alpha+\beta+\Gamma=-4\]

Answer 3

how is alpha 2

Answer 4

Just to mention, @Jonask shows you a cute property of quadratic equation
a^2 + bx + c =0;
The sum of the two roots is -b.

Answer 5

For alpha,
x-2 = 0
x = 2
or alpha = 2

Answer 6

for beta (-b+-root of
right??

Answer 7

For beta and gamma, Jonask wrote that already.
But you can find beta + gamma directly, it's equal to -b = -6