Question

The value of \[6+\log_{\frac{ 3 }{ 2 }}(\frac{ 1 }{ 3\sqrt{2} }\sqrt{4-\frac{ 1 }{ 3\sqrt{2} }\sqrt{4-\frac{ 1 }{ 3\sqrt{2} }....}} \]

Answer 1

Did you simplify the surd?

Answer 2

Yup...)

x= sqrt4-1/3sqrt2 sqrt4-1/3sqrt2......

squaring

x^2 = 4 - 1/3sqrt2 *x

Answer 3

You get,
x = \[4 \sqrt2 /3\], Correct?

Answer 4

^^ The other value of x is a negative one, so only this is viable.

Answer 5

i got \[x=\frac{ 8 }{ 3\sqrt{2} }\]

Answer 6

Let us go with ur x...)

Answer 7

It's the same.

Answer 8

Silly...yes....

Answer 9

Nw wat to Do

Answer 10

After that its simple.
You've done all the hard work.

Answer 11

\[\log_{\frac{ 3 }{ 2 }}(\frac{ 4 }{ 9 }) \]

Answer 12

\[\log_{3/2}(2/3)^2 = - 2\log _{3/2}3/2 = -2\]

Answer 13

Yup,,,,,).. thxxxx

Answer 14

So you get 4. :)

Answer 15

:)

Answer 16

i want to study logarithms More.......Can....assist me..

Answer 17

i mean...Do u knw any Gud videos on that Topic which i can get

Answer 18

Khan acedemy.
best option :)

Answer 19

Thxxx.) again