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Mathematics 18 Online
OpenStudy (anonymous):

Let z be a complex number such that imaginary part of z is non zero and a=z^2+z+1 is real then a cannot take the value?

OpenStudy (anonymous):

z=x+iy evaluate the value of a in terms of x and y

OpenStudy (anonymous):

x^2 + 2xiy - y^2 + x + iy + 1 = a

OpenStudy (anonymous):

\(y\neq0\) and\[2xy+y=0\]right?

OpenStudy (anonymous):

Why? 2xy + y =0

OpenStudy (anonymous):

because a is a real number

OpenStudy (anonymous):

got it.....

OpenStudy (anonymous):

2xy+y=0 and \(y\neq0\) so\[2x+1=0\]

OpenStudy (anonymous):

do u know why \(y\neq0\)

OpenStudy (anonymous):

if y=0 then imaginary part becomes 0

OpenStudy (anonymous):

\[x=-\frac{1}{2}\]so a becomes\[a=\frac{3}{4}-y^2\]am i right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so whats the value that a can not take considering \(y\neq0\) clearly\[a\neq\frac{3}{4}\]we are done :)

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