Question

A line perpendicular to x + 3y = 5 passes through (1, -1). What is the equation of the line in standard form?

Answer 1

Thanks but how did you get it?

Answer 2

Alright...First, write the equation of the first line in the standard form as

3y=5-x
y=(5/3)-(x/3)

Therefore, the slope of the above line is -1/3

Now, you can simply get the slope of the perpendicular line as

Answer 3

m2=-(1/m1)=-(1/-(1/3))=3

So, the equation of the new line is

y=m2x+b=3x+b

but this line passes through (1,-1)...substitute the point into the above equation you get

-1=3(1)+b --> b=-4

Therefore,

y=3x-4

Answer 4

Oh wow. Thank you so much

Answer 5

No problem :)