Question

In 4a)

http://ocw.mit.edu/courses/mathematics/18-01sc-single-variable-calculus-fall-2010/exam-3/materials-for-exam-3/MIT18_01SCF10_exam3sol.pdf

How do we find the formula for hypotenuse of the triangle?
(h-hx/r)

(Just for x)
(Sorry, somehow this question got closed before)

Answer 1

you ask how they got y = h- hx/r ?

Answer 2

yes

Answer 3

we have two points :

( 0,h) and (r,0)

Answer 4

hence the slope : (h-0) /(0-r) = -h/r

and using y = y1 + m(x-x1)

we get :
y = h -hx/r

Answer 5

sorry, why are we using h for y1?

Answer 6

i can see how we get the slope

Answer 7

we can take one of the points :
(0,h) or (r,0)

to be (x1,y1)
in both cases we will get the same answer

Answer 8

lets take the (r,0) so y1 = 0 :

y = 0 + -h/r(x-r)
y = h -hx/r

Answer 9

indeed O_O

Answer 10

we find slope then we can choose any given point on the line to construct our line equation :)

Answer 11

yes

Answer 12

great, got it, thanks :)

Answer 13

yw