Find the identical expression for 1-sin^4theta/1+sin^2theta
1-sin^4theta=(1+sin^2theta)(1+sin^2theta) so, it all simplifies to 1+sin^2theta.
none of my answer choices are 1+sin^2theta
plus you missed the 1+sin^2theta on the bottom
he must have meant 1-sin^2theta= cos^2 theta
is cos^2 theta in options ?
yes it is
good :)
so how exactly do I solve it then?
1-sin^4theta this is a difference of two squares so factorise it (1+sin²theta)(1-sin²theta) so now you have (1+sin²theta)(1-sin²theta)/1+sin^2theta this cancels out to 1-sin²theta 1-sin²theta=cos²theta
1-sin²theta=cos²theta this comes from sin²theta + cos²theta=1 rearrange 1-sin²theta=cos²theta
do you understand?
1-sin2teta=cos2teta
@mahmit2012 that is wrong, sin2theta has its own identity sin²theta is not sin 2 theta
yes I think I understand, thank you!
I wrote sin^2 !! check it out .
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