A drawer holds 4 red hats and 4 blue hats. What is the probability og getting exactly 3 red hats or exactly three blue hats when taking out 4 hats randomly out of the drawer and immediately returning every hat to the drawer before taking out the next? a.½ b. 1/8 c . ¼ d. 3/8
there is conflict between a and b
wait for a min...or till then can u write ur steps?
finding 4 out of 8 (4/8*4/8*4/8*4/8)=1/16 1/16+1/16=2/16=1/8
but why the conflict between a and b?
when i google it i got another one i mean 1/2 thats why!!!!!!!!
U get the answer on google also!
yes on m4maths
The binomial distribution applies to this problem. The probability of getting exactly three red hats or exactly three blue hats is given by: \[\left(\begin{matrix}4 \\ 3\end{matrix}\right)\times (0.5)^{3}\times 0.5=4\times (0.5)^{3}\times 0.5=?\]
Required probability is 1/4.
you are not going right
@savi Do you understand the binomial distribution?
i knew it but its a short time tricky question ,there are many way to solve it ,but i want an easy one
4!/3! * (1/2)^4 = 1/4
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