If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the second and third equations, then the first and second equations. 5x + 2y + z = -23x + 4y + 3z = 2-4x - 3y - 3z = 1 Answer 5x + 2y = -23x + 4y = 2 -x + y = 3-12x - 2y = 8 5x + 2y = -2-12x - 2y = 8 x - y = -33x + 4y = 2
The answer I have is B........
those are the equations ? 5x + 2y + z = -2 3x + 4y + 3z = 2 -4x - 3y - 3z = 1
Yes
in order to eliminate z from the second we multiply the first by 3 and then subtract the first from the second : 3x + 4y + 3z = 2 minus 15x +6y+3z= -6 = -12x -2y = 8
It's either B, or c
:)))
oh wait they want the first and second ? why i saw third :O
:( I find no encouragements in any of this.
ok so second from third we just add the equations 3x + 4y + 3z = 2 + -4x - 3y - 3z = 1 and get -x +y = 3
so bravo ! it is B:)
Oh my gosh ;')
I won!!!!!!!!!!!!!!!!!!!!! I understand!!!!!!!!!!!!!!!!!! :))))))))))Thank you!!!!!!!!!!!
yw:)
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