How do I solve an exponential equation like this:
37 = 22 + 1(2.2)^3.4x

Question

How do I solve an exponential equation like this:
37 = 22 + 1(2.2)^3.4x

anonymous · Answer

take it easy...,

anonymous · Answer

similar with 

a = b + c(d)^3 . 4x
a - b =  c(d)^3 . 4x
4x = (a-b) /  c(d)^3 .
x = (a-b)/ (4. c(d)^3)

i believe you can.., ok

anonymous · Answer

I don't understand how the third line broke apart the 3.4 in the exponent.  I just noticed there's an equation thingy for replies, so I'll use that for the equation just in case.  Thank you for replying!
$$37 = 22 + 1(2.2)^{3.4x}$$

anonymous · Answer

I believe it will be algebraically simplified to the following, but I don't know what to do from there:
$$15 = 2.2^{3.4x}$$

anonymous · Answer

yes @BloopityBloop  .., maybe

using logaritm.

$$15 = 2.2^{3.4x}$$
$$^{2.2} \log 15 = 3.4x$$

so x = 

i believe you can @BloopityBloop

anonymous · Answer

$$^{2} \log 8 = 3  $$ equal to $$2^{3} = 8$$

anonymous · Answer

sorry in indonesia.., $$^{a} \log{b} = c $$ equal to  $$\log_{a}b = c  $$

how?? can I hep you again?

anonymous · Answer

yeah, it was the log I'm not too good with.  I think I need to take the log of both sides, then simplify with algebra.  I got:
$$x = \frac{ \ln(15) }{ 3.4 \ln (2.2) }$$
Thanks for your help!

anonymous · Answer

great job @BloopityBloop your the best :)