Conventially, the converse isn't true, right?
the rule is that only the contrapositive is equivalent to its conditional statement...
Talking to @jazy and @sauravshakya in the math chat, I found out a counterexample: “If a student is \(\rm x\) years old, then he is in grade \(\rm x + 5\).”
mmhmm
and?
The contrapositive is true! If a student is not in grade \(\rm x + 5\), then he is not \(\rm x\) years old.
yes. that's what i said
Yeah, so the contrapositive is equivalent to the conditional, and the converse is true.
the only time the converse is true is when the statement is biconditional
converse is not equivalent to the conditional
How so?
I mean, isn't what I said true?
p q p -> q q -> p T T T T T F F T F T T F F F T T not equivalent
I mean that... here, p -> q is also true and q -> p is also true.
\[q \rightarrow p \equiv p \rightarrow q\] \[\neg q \vee p \equiv p \rightarrow q\] \[p \vee \neg q \equiv p \rightarrow q\] \[\neg(\neg p) \vee \neg q \equiv p \rightarrow q\] \[\neg p \rightarrow \neg q \equiv p \rightarrow q\] see how they're not equivalenT/
anyway....you were saying?
Wait, where exactly is the fallacy?
“If a student is x years old, then he is in grade x+5" is not the same as "If a student is in grade x + 5, then he is x years old"
Yes, it is...
q -> p is equivalent to ~p-> ~q not p->q
If we kick the truth tables out, then they essentially mean the same.
logical equivalence are not the same either
and like i said... “If a student is x years old, then he is in grade x+5" is not the same as "If a student is in grade x + 5, then he is x years old"
wanna see how?
in a way...you can call it a counter-counterexample
Join our real-time social learning platform and learn together with your friends!