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Mathematics 17 Online
OpenStudy (anonymous):

a,b satisfies the equation

OpenStudy (anonymous):

\[a^3-3a^2+5a-17=0\] \[b^3-3b^2+5b+11=0\] find\[a+b\]

OpenStudy (anonymous):

\[a^3+b^3=(a+b)(a^2-ab+b^2)\] -3(a^2+b^2)-5(a+b)\[-3(a^2+b^2)-5(a+b)+6=(a+b)(a^2-ab+b^2)\] \[a+b=\frac{ -3(a^2+b^2) -5(a+b)+6}{ a^2-ab+b^2}\] is that correct

OpenStudy (anonymous):

a+b is a real number

OpenStudy (anonymous):

Well yeah it's correct.. :)

OpenStudy (anonymous):

but it has to be a number

OpenStudy (anonymous):

You mean the answer.. ?

OpenStudy (anonymous):

yes

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