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OpenStudy (daenio):
What is the concentration of H+ in a solution containing 73.0g of HCL in 500 mL of water?
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OpenStudy (anonymous):
H+ = 73/36.5 * 1 = 2gm of H+ no of moles = 2/1 = 2 Concentration (Molarity (M) = \[\frac{ 2*1000 }{ 500 } = 4M\]
OpenStudy (daenio):
I actually figured this one out. Thanks for confirming the solution! :D
OpenStudy (anonymous):
Welcome
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