Question

Solve using law of sines A = 41°, B =61°, c = 19

Answer 1

law of sines
\[\frac{ \sin A }{ a }=\frac{ \sin B }{ b }=\frac{ \sin C }{ c }\]
\[\frac{ \sin 41 }{ a }=\frac{ \sin 61 }{ b }=\frac{ \sin C }{ 19 }\]

Answer 2

\[
A+B+C=180^\circ\\
41^\circ+61^\circ+C=180^\circ\\
C=180^\circ-41^\circ-61^\circ\\
\ \ \ =78^\circ\\
\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}\\
\\a=c\frac{\sin A}{\sin C}\\
\\b=c\frac{\sin B}{\sin C}\\
\text{The rest is left as exercise to you.}
\]

Answer 3

nvm i think i got the answer