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Calculus1 20 Online
OpenStudy (poofypenguin):

Help Please! Attachment to come...

OpenStudy (poofypenguin):

OpenStudy (zzr0ck3r):

do you know the product rule?

OpenStudy (anonymous):

Do you to simplify your equation ? and i didn't understand what you have to do with \[g(x)\]

OpenStudy (anonymous):

I think the quadratic formula has no real roots.

OpenStudy (anonymous):

\[f'(x)=(4t+5)\cos t -(4t^2+5t+7)\sin t\] it's not simplify

OpenStudy (zzr0ck3r):

4t^2+5t+7*cos(t) so product rule says take the derivative of one and leave the other alone and add it to the opposite (8t+5)cosx+(-sinx)4t^2+5t+7

OpenStudy (poofypenguin):

alright! that makes sense...now what about the one with the "e"?

OpenStudy (zzr0ck3r):

same thing, what do you not understand?

OpenStudy (poofypenguin):

I understand the product rule now, but how do you differentiate the "e"?

OpenStudy (zzr0ck3r):

derivative of e^x = e^x

OpenStudy (anonymous):

it's \[g'(x) = (8t+5)e^t + g(x)\]

OpenStudy (zzr0ck3r):

nope

OpenStudy (anonymous):

realy ?

OpenStudy (zzr0ck3r):

(4t^2+5t+7)e^x+(8t+5)*e^x

OpenStudy (poofypenguin):

alright! that makes perfect sense! thanks so much for helping me everyone! :D

OpenStudy (anonymous):

@PoofyPenguin in the attachment ...are those both seperate questions , or interrelated to each other?

OpenStudy (zzr0ck3r):

f(t) and g(t)

OpenStudy (poofypenguin):

i'm pretty sure that they're completely separate questions...

OpenStudy (anonymous):

thanks. i was not getting taht's why i asked for.

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