Question

Solve the following differential equation : sin x dy/dx + cos x.y = cos x.sin2 x

Answer 1

what are you doing in class? Are you solving with eigen values? laplace transforms?undetermined coefficients?,,,

Answer 2

what u wana say @zzr0ck3r

Answer 3

divide the equation throughout by sinx

Answer 4

\[\sin(x)*dy/dx + \cos(xy) = \cos(x)*\sin^2(x)\]

Answer 5

correct?

Answer 6

No, I think it's double angle, not sin squared. That's what I think. The problem is that people don't always type accurately.

Answer 7

well then no point in me trying on this one.... Gotta be explicit people!

Answer 8

I agree. I think it's best to leave it alone until the person comes back on line. Til then time to move on to new adventures.

Answer 9

there is another way to do it let me show you

Answer 10

@shruti if you mean\[\sin x \frac{ dy }{ dx }+y \cos x =\cos x \sin 2x\]then this is a first-order linear equation and can now easily be solved. If and when we're both on line, thae I can teach you if you need it. I'll be here for about thirty more minutes right now.

Answer 11

\[\sin (x) \frac{\text dy}{\text dx} + y\cos (x) = \cos (x)\sin^2 (x)\]

\[ \frac{\text dy}{\text dx} + y\cot (x) = \cos (x)\sin (x)\]

Answer 12

@shruti, please clarify the question,

if by sin2 x you mean sin^2 x, then i have a ful solution we can work through