The altitude of a triangle is increasing at a rate of 3.0 centimeters/minute while the area of the triangle is increasing at a rate of 2.0 square centimeters/minute. At what rate is the base of the triangle changing when the altitude is 11.5 centimeters and the area is 91.0 square centimeters?
area of a triangle = 1/2 base* height
differentiate this equation wrt time
u can write A= 1/2 b* h
can u differentiate this equation wrt time?
what will the equation that i have to differentiate be? what numbers would i sub in?
differentiate this equation A= 1/2 b * h A= area o the triangle b= base h= height
supposes u have been given x= 2t^2 and i ask u to differentiate this wrt t(time)
x is the distance traversed..and if u differentiate it then u'll get the speed...right?
forget the substitution part for now...that will come later
x= 2t^2 differentiate x wrt time
x=4t?
it'll be dx/dt= 4t
differentiation of x wrt t= dx/dt
im confused
what's ur confusion?
I gave u an equation x=t^2 and asked u to differentiate wrt t
i got the equation for my problem to equal 2=(1/2)dB/dT * 11.5+dH/dT*(1/2)b
is that correct?
A= 1/2 b * h dA/ dt = 1/2( db/dt *h + b * dh/dt) 2= 1/2 ( db/dt *h + b*3)
u have been given dh/dt= 3cm/minute
now u have to find db/dt when h=11.5 and A=91 cm^2
see this equation 2= 1/2 ( db/dt *h + b*3) for finding db/dt u need to know b and h..but u know h only so find b
for finding b,use A= 91 cm^2
b=.063107 ?
A=91, h=11.5 then b=?
b=15.82 cm
2=1/2(db/dt) *11.5+15.82*3 ?
2=1/2(db/dt) *11.5+1/2 * 15.82*3
u left 1/2 in the 2nd term of RHS
so find db/dt that will be the answer.
i got -.778223 but its telling me its the wrong answer
how did u come to know that it's wrong answer?
due to -ve sign?
the retriceinment is online to i entered the answer, and its telling me its wrong
let me check
assignment*
enter this value db/dt=-3.77
is it right?
no its coming up incorrect
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