Question

When sodium is excited in a flame, two ultraviolet spectral lines at (wave length symbol)=372.1 nm and (wave length symbol)=376.4 nm respectively are emitted. Which wavelength represents photons with

a) high energy?
b) longer wavelengths?
c) higher frequencies?

Answer 1

higher energy = shorter wavelength

frequency is one cycle over an amount of time (seconds)

so higher frequency = higher energy = shorter wavelength

Answer 2

ps the "wavelength symbol" is called lambda