you have a piggy bank containing 78 coins in dimes and quarters. If the piggy bank contains $12.60, how many dimes in the piggy bank?
so if q = quarters and d = dimes
q+d=78
.25q+.10d=$12.60
that's perfect, now just solve the system
ok so i would multiply 4 through out equation 2 right?
personally, I would use substitution instead
like .25q=$12.60-10d?
q+d=78 q= 78-d 0.25q+0.10d=$12.60 0.25(78-d) + 0.10d = 12.60
the first equation is much easier to solve for one variable, then sub into the other.
19.5-0.25d+0.10d=12.60 turns into 19.5+.15d=12.60 and then .15d=6.9?
so how many dimes were in the bank? then we know from before that q= 78-d
46 dime and 15 q?
your quarters is wrong, use q= 78-d
oh thought it was suppose to be 61 coins my mistake but then q=32?
right, good job.
wow thanks the way teacher taught me was confusing is substitution easier in these situations?
when you are dealing with decimals, and small number, substitution is generally easier as you cannot always find a convenient multiple
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