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The width of a square-based storage tank is 3m less than its height. The tank has a capacity of 20 m3. If the dimensions are integer values in metres, what are they?
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Let h denote the height, so the width is h-3. Volume = h(h-3)² = 20 h(h²-6h+9) = 20 h³-6h²+9h = 20 h³-6h²+9h-20 = 0 (h-5)(h²-h+4) = 0 h-5 = 0 h = 5 The dimensions are 5m by 2m by 2m. I hope this helps.
how did you get from \[(h-5)(h ^{2}-h+4)=0\] to (h-5)=0 ?
--->(h-5)<---(h²-h+4) =--->0<---=h-5 = 0
i still don't get it...
because (H-5)(h2-h+4)=0 so we put it together=H-5 so H-5=0 and that's the answer
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oh okay thanks
your welcome
I still domt get why h-5. Equals to zero . .
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