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Mathematics 18 Online
OpenStudy (anonymous):

how do i find the vertical asymptote?

ganeshie8 (ganeshie8):

do u have a rational function ?

OpenStudy (anonymous):

yea its f(x)=x-2/x^2-5x+6

ganeshie8 (ganeshie8):

a vertical asymptote or a hole occurs when denominator approaches 0

ganeshie8 (ganeshie8):

start by factoring he denominator

ganeshie8 (ganeshie8):

x^2-5x+6 could u factor this

OpenStudy (anonymous):

(x-3)(x-2)

ganeshie8 (ganeshie8):

so we have a common factor !

ganeshie8 (ganeshie8):

\( f(x) = \frac{x-2}{(x-2)(x-3)} \)

ganeshie8 (ganeshie8):

\((x-2) \) cancels top and bottom, right ?

OpenStudy (anonymous):

yes

ganeshie8 (ganeshie8):

and denominator becomes 0, when x = 2, or x = 3

ganeshie8 (ganeshie8):

but since (x-2) is getting cancelled, it is just a hole. its not a vertical asymptote since (x-3) is not getting cancelled, it is a proper vertical asymptote

ganeshie8 (ganeshie8):

x-3 = 0 x = 3 we say the line x = 3 is the vertical asymptote of rational function

OpenStudy (anonymous):

thanks i understand now

ganeshie8 (ganeshie8):

glad to hear :)

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