Question

could someone please show me how to work this problem out ....



C = 5/9 (F - 32) solve for F?

Answer 1

you cant?

Answer 2

oh wait you just want F on its own?

Answer 3

it's 5 over 9 not 5 divided by 9

Answer 4

ya i just don't fully get the concept

Answer 5

\[C = \frac{5}{9}(F - 32)\]

Answer 6

celcius to farenheight?

Answer 7

ya but i wan't to find out what F is

Answer 8

" farenheight"

Answer 9

its the same as this \[C = \frac{5(F-32)}{9}\]

Answer 10

\[9C = 5(F-32)\]

Answer 11

see what i did there? multiply by 9

Answer 12

then divide by 5
\[\frac{9C}{5} = F -32\]

Answer 13

then add 32 to both sides \[\frac{9C}{5} + 32 = F\]

Answer 14

get what i did?

Answer 15

sorta

Answer 16

\[F= 32+\frac{ 9C }{ 5 }\]so you got

Answer 17

yah

Answer 18

COOL THANKS FOR EXPLAINING IT

Answer 19

np