OpenStudy (anonymous):

How to find the domain of a function? Show me step by step.

OpenStudy (jim_thompson5910):

What is the function?

OpenStudy (anonymous):

One is $\sqrt{x-2}$

OpenStudy (jim_thompson5910):

you can't take the square root of a negative number

OpenStudy (jim_thompson5910):

so x-2 can't be negative

OpenStudy (jim_thompson5910):

this means $\Large x-2 \ge 0$ solve that for x

OpenStudy (anonymous):

But how do I know how to set it up like that? I am so confused? Why Greater than or not less than or equal to?

OpenStudy (jim_thompson5910):

because x-2 must be either a) zero or b) positive since x-2 can't be negative

OpenStudy (jim_thompson5910):

if x - 2 were less than or equal to zero, then x-2 would be negative...which is what we don't want

OpenStudy (anonymous):

Okay, so it's x=2.

OpenStudy (jim_thompson5910):

close

OpenStudy (jim_thompson5910):

more like $\Large x \ge 2$

OpenStudy (anonymous):

Okay, do you mind me trying a few and see if I end up with the correct answer?