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Mathematics 8 Online
OpenStudy (anonymous):

How to find the domain of a function? Show me step by step.

jimthompson5910 (jim_thompson5910):

What is the function?

OpenStudy (anonymous):

One is \[\sqrt{x-2}\]

jimthompson5910 (jim_thompson5910):

you can't take the square root of a negative number

jimthompson5910 (jim_thompson5910):

so x-2 can't be negative

jimthompson5910 (jim_thompson5910):

this means \[\Large x-2 \ge 0\] solve that for x

OpenStudy (anonymous):

But how do I know how to set it up like that? I am so confused? Why Greater than or not less than or equal to?

jimthompson5910 (jim_thompson5910):

because x-2 must be either a) zero or b) positive since x-2 can't be negative

jimthompson5910 (jim_thompson5910):

if x - 2 were less than or equal to zero, then x-2 would be negative...which is what we don't want

OpenStudy (anonymous):

Okay, so it's x=2.

jimthompson5910 (jim_thompson5910):

close

jimthompson5910 (jim_thompson5910):

more like \[\Large x \ge 2\]

OpenStudy (anonymous):

Okay, do you mind me trying a few and see if I end up with the correct answer?

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