Question

Solve the following equations for all solutions of x

cotxcos^2x=2cotx

Answer 1

equate to zero .. . .

(cot x)(cos^2 x) - (2cot x) = 0

then factor completely
(cot x) (cos^2 x - 2) = 0
(cot x) (cos x - √2) (cos x + √2) = 0

then
either
cot x = 0
cos x = √2 ≈ 1.4
cos x = -√2

but cosine values cannot be outside -1 and 1

thus only cot x = 0 would yield solution
and the answers are .. . .. .
π/2 and 3π/2

Answer 2

is that helps u @KBeard

Answer 3

Yes, that helped so much. I am having trouble identifying where to start. Thank you!